Thursday 19 January 2012

Row 5


Since we know that numbers cannot repeat in any column, we can logically ascertain (now that we've entered 5s in blocks 3 & 5) that some of the 5s we pencilled in for blocks 8 and 9 are no longer possibilities. So let's remove those 5s.
And lo and behold, now we have only one possible placement for 5 in those two blocks.
That completes the number 5 since every block now contains a 5. So where do we go from here?

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