Thursday, 19 January 2012

Final complete

There is only one empty cell left in row 7 so we can enter the 1 there. Entering the 1 in row 7 eliminates all other possibilities for the 1 in block 2 so we can enter a 1 in the lower left-hand cell. Entering the 1 in row 3 eliminates one of the possibilities for the 7 in that block so we can enter the 7 and that in turn eliminates one of the two 7s in block 8 and allows us to enter the 7 there. Checking column 4, we need to place the 4 and 9. There's already a 4 in row 2 so the 4 must go in row 5 and the 9 in row 2.In row 5 we are missing the 3 and 9. The 3 has to go in block 4 (there is already a 9 there) and the 9 in block 5. This leaves one empty cell in each of these blocks. So enter the 3 and the 4 in their respective...

Row 9

The rest of this tutorial is for novices who would like to see the entire solution covered. Looking over the grid we can see that block 6 requires a 2 and since column 8 and row 6 already contain a 2, we can eliminate all the cells in the block except the one in the upper right-hand corner, so enter a 2 there. Now column 9 is missing the 3, 4, 6 and 9. There is already a 9 in block 9 so the 9 must go in the bottom-right cell of block 6.Looking at the bottom cell of column 9, we can eliminate the 3 and 4 as they both appear in row 9, so the 6 must go there. Placing that 6 eliminates all but one cell for the 6 in block 8. Now there's only one cell for the 6 in column 3 and that eliminates all but one cell in block 4 for...

Row 8

Up to now, our strategy has been to enter all the possibles for any number with a high frequency rate within the puzzle. Now, we've got enough numbers entered into the grid that we can use a different solving strategy. Let's look at block 3. We have seven of the nine numbers required. We are missing only the 3 and the 9. Looking at the top row, we see that it already contains a 3 (in block 2). Therefore, the 3 must go in the bottom left square of block 3 and (Eureka!) the 9 in the last remaining square. Wow! We've come along way towards solving this puzzle.And on further examination we see that the only number missing in column 7 is the number 2. So we can enter it in block 9. Now you have the basic solving strategy for SuDoku...

Row 7

Now, we'll fill in the 7 in block 6 and the 8 in block 3. Again, we can eliminate one of the 8s in block 2.That leaves a single square for the 8 in block 2.So we can enter the 8 and that completes the 8s for this puzzle.Now, it's time to change our solving strate...

Row 6

Now, we'll follow the same procedure for the 7s. Again, we have only one possible placement fo the 7 in blocks 3 and 4.Now we can safely enter those numbers and remove any 7s from the corresponding rows or columns. And that leaves only one possibility for the 7 in block 6. And it also nails down the 8 in block 3! Now, we're making progre...

Row 5

Since we know that numbers cannot repeat in any column, we can logically ascertain (now that we've entered 5s in blocks 3 & 5) that some of the 5s we pencilled in for blocks 8 and 9 are no longer possibilities. So let's remove those 5s. And lo and behold, now we have only one possible placement for 5 in those two blocks. That completes the number 5 since every block now contains a 5. So where do we go from here?...

Row 4

  The number 5 also appears five times within the puzzle so now we'll follow the same procedure for the 5s. Once again, we have only a single cell in blocks 3 and 5 where a 5 can possibly be placed. Now we enter the number 5 in block 3 and 5. Now, here's where it gets interesting....

 
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